I want to do some calculations for two diesel engines drive a ship propeller through a gearbox. I want to know the speed reduction ratio, total inertia of the system, torque ratio, etc.
I know that the power delivered at the propeller which rotates at 150 rpm will be equal to the sum of power of the two engines running at 750 rpm.
P(load) = 2*p(eng)
T(laod) * 150 = 2*750*T(eng)
Is the speed reduction ratio is different from torque ratio ? is (2*750)/150 the correct reduction ratio ? or it is just 750/150 ?
Also, to model the shaft dynamics, i will use the following equation:
2*pi*Inertia of rotating parts*(dn/dt)= T(eng) - T(propeller) - T(friction)
The total system inertia at the shaft = inertia of propeller including entrained water + shaft + gearbox + engine inertia*(reduction ratio^2) ????
Many Thanks in advance
Your calculations are write, speed ratio: number of teeth on 1st gear *number of revolution of that gear = number of teeth on 2nd gear *number of revolution of 2nd gear
Torque ratio: Power is same i.e. Torque on first gear*angular velocity of the first gear= Torque on second gear*angular velocity of the second gear
Thank you Mr Patel for your kind reply and help.
So in my case speed ratio is 5 and torque ratio is 10 ?
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