During a condensation process,at a particular temperature the water vapor condenses into water liquid. How can we relate the mole fraction/mass fraction of vapor with temperature?
formula relating mass fraction/ mole fraction with Temperature!
Dear Jibin: we need more information as the question/ problem posed is too vague.
How many components has the gas and liquid phase.
The conversion between mole/mass fraction is the molecular weight of the components==>
Mass of A = [number of Moles x Mw ] of A
Mass of B = [number of Moles x Mw] of B
weigth fraction of A = mass A / (mass A + mass B)
regarding Temperature= as the temperature drops the relative humidity (molar fraction) decreases and can be obtained as the change in dew point with temperature.
If you assume thermodynamic equilibrium between the steam and condensate, and gaseous phase as ideal gas, then the partial pressure of steam is equal to the saturation pressure at system temperature.The partial pressure for an ideal gas mixture is equal to product of the molar fraction and the total pressure (Pi=yi*P).
This approach will give you only an approximation as is based on ideal behaviour of the gas mixture and phase equilibrium.
Thanks for your reply Mr Carlos A. Grattoni and Mr Johane Bracamonte
The problem I am referring to is a condensation problem.
In a circular tube of height 6m and dia 2.5cm hot water vapour is entering the inlet at a temperature of 150°C. Water liquid is flowing over the tube such that the surface temperature Ts is 15°C. In this process the condensation of steam takes place and we get water at exit.
So in this case that mass fraction of water-vapour will vary from 1 at inlet to "x" at outlet. I would like to quantify the "x" relating it with either temperature or pressure or any other means.
Please could u give your valuable suggestions.
I recommend you to read this paper:
http://ijens.org/Vol_18_I_05/180505-3737-IJMME-IJENS.pdf
Best regards
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