I have doped Ti in ZnO using a chemical method. The FESEM results are showing a reduction in the average diameter of ZnO nanorod after the Ti doping. Can someone help me to explain that? Thanks
How have you done it? Doping? May be diameter was changed with another factor.
a) This may be due to the dissolution of ZnO interface of nanorods because of the fact that the chemical affinity of Tİ for TiO formation is much higher than the Zn affinity to form ZnO. This is a conventional explanation without numerics!
b)Another explanation may be given by using the concept of global Helmholtz free energy reduction by reducing the surface free energy of ZnO rods associated with the cylindrical wall just increasing its Helmholtz interfacial free energy density with the surrounding solution through Ti doping. Since the surface free energy= Area x Interfacial free Helmholtz energy density. Where: area= rod length x 2pi Radius.
This statement can be easily put into a rigorous mathematical format by including bulk Helmholtz free energy variation due to spontaneous length increase to keep the volume constraint to find the optimal nanorod radius and length.
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