I was recently told that the maximum skin depth (δ) used in waveguides is 6δ. Usually it is kept to a maximum of 5δ, as the waves cannot penetrate beyond this at high frequencies. Why is it 6δ and what is the reason for it?
Skin Depth is a measure of how closely electric current flows along the surface of a material. At d.c. (0 Hz or a constant voltage), electric current flows uniformly through a conductor. This means the current density is the same everywhere. However, at higher frequencies, the current prefers to flow along the surface, producing surface current. The skin depth equation is given below:
skin depth = (p/pi*f*mu)1/2
where p=is the resistivity of the material (in Ohms/meter; this is the inverse of conductivity),
mu= is the permeability of the material (a measure of the magnetism),
f= f is the frequency of the current.
pi= Irrational number pi (approx. 22/7)
thus resistivity, permeability depends on material n when we put its value and in certain frequency thus it gives the value of skin depth approx. 5.3
Skin Depth or δ is distance in which wave's amplitude reduces to e^-1 or 0.368 of its value, So if it travels 3δ it has a 0.049 of initial amplitude and if it has travels 5δ almost it absorb totally in lossy material.
I understood from various sources that the maximum skin depth needed is 5δ. But my professor informed me that it is not 5δ, but it is 6δ in waveguides.
The formula for skin depth was given by Dhanu, above. It applies for all conducting materials and frequencies. At 10 GHz the skin depth is less than a micron in copper, silver or gold. At 50 Hz it is about 8.5 mm so cables more than 4 cm across are wasting a lot of copper. Look up skin depth in Wikipedia.