I was calculating MSE and the result of division turned up to be zero. I would like to use the fractional part of answer also. Suppose the answer is like this 0.0089 . The answer being shown in matlab WORKSPACE is MSE 0.
Check your current format and confirm it to be 'long' (as suggested by Khademi). I don think there should be any other problem as Matlab uses double as its default data type. Check whether you or your function uses - floor or fix functions. As these are used to round off and to separate the integer and fractions.
Can you please be more specific in your questions. So that someone could help out. What Matlab function you are using ? or have you written function to find MSE ? If so post it.
this is my code which i am trying
format long
I = imread('building128_128.tif');
I1 = imnoise(I,'gaussian');
f = [];
f1 = [];
MSE = 0;
a = 0;
[m,n] = size(I);
f = I;
[m1,n1] = size(I1);
%imshow(I1);
f1 = I1;
for i =1:m
for j=1:n
a = (f(i,j)-f1(i,j))*(f(i,j)-f1(i,j));
MSE = MSE + a;
end
end
fprintf('%f',MSE);
% MSE = MSE/(m*n);
% fprintf('%f',MSE);
%PSNR = 10 * log10((255*255)/(MSE));
building is an 128*128 image
Check the input image class I. It would be of the class ( - unsigned integer) which other than double and hence the MSE value is 0 even it is 0.0089.
Convert the input image I to be of class double. It would solve your problem.
I used im2double function and the code worked
thks to both sriram and april khademi
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