The standard deviation is defined as the square root of the variance. From this definition, the variance will be less than the standard deviation if it's < 1. For example, if variance = 0.01, then std = squareroot(variance) = 0.1 > variance.

I don't understand your definition of variance in terms of the standard deviation divided by mean...

HTH,

Domingo

Standard deviation divided by mean is CV (coefficient of variation)

now I'm also have this problem. my data is not normal distributed and i get variance as 0.45 then sd is 0.65 approximately. what does it mean? how we can interpret this condition?

thanks in advance.

https://www.reddit.com/r/AskStatistics/comments/4zdvto/variance_standard_deviation_relationship_when/