The hall coefficient is defined considering the applied field in Tesla and thickness of the specimen in Meter. When we wish to represent the hall coefficient in terms of cm/G, the factor to be multiplied with (m/T) comes out to be 10^6. Then why is a factor of 10^8 used ?
Dear Vishal Saravade,
the Hall coefficient AH[m³/C] is converted via 1m=100cm to
AH[m³/C]= AH [1003 cm3/C]= AH*106[cm³/C]; so far your conversion factor 106 is right.
But going from magnetic field B divided by distance d:
B/d[T/m] to [G/cm]-units you have to use 1T=10000G and 1m=100cm as above.
So you have : B/d[T/m] =B/d[10000G/100cm] =B/d*10000/100[G/cm]=B/d*100[G/cm].
Now your Hall voltage UH is given by (I being the electric current):
UH = I * AH[m³/C] *B/d[T/m] = I * AH*106[cm³/C] *B/d*100[G/cm]=
= I * AH*108[cm³/C] *B/d*[G/cm]
Here in the calculation of UH your conversion factor 108, which you mentioned above, pops up.
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