I am assuming the density of your fiber is 2.54 g/cc (where cc is centimeter cubed) and the density of polypropylene (PP) is 0.90 g/cc.

• 100 g PP/ (0.9 g/cc) =111.11 cc volume of PP
• 111.11 cc = 0.7 * total volume of sample (VT)
• VT = (111.11 cc)/0.7 = 158.73 cc
• volume of fibers (Vf) = 158.73 cc - 111.11 cc = 47.62 cc fibers
• Converting to mass = 47.62 cc fibers * 2.54 g/cc = 120.95 g fibers

So, 120.95 grams of fibers per 100 grams of polypropylene.

Substitute in your values for density if the numbers are different. The math flow will be the same.

Regards.

To determine how many kilograms of E-glass fibers are in the composite for every 100 kg of polypropylene, we can use the following formula:

fiber mass fraction = (fiber volume fraction) x (fiber density) / [(fiber volume fraction) x (fiber density) + (matrix volume fraction) x (matrix density)]

Assuming that the density of E-glass fiber is 2.6 g/cm^3 and the density of polypropylene is 0.9 g/cm^3, and using the given fiber volume fraction of 30%, we can calculate the fiber mass fraction as follows:

fiber mass fraction = (0.3) x (2.6 g/cm^3) / [(0.3) x (2.6 g/cm^3) + (0.7) x (0.9 g/cm^3)]

= 0.286

This means that for every 100 kg of polypropylene in the composite, there are 0.286 x 100 kg = 28.6 kg of E-glass fibers.

Tariq Mir

I am using the numbers you have provided, and the same equation you posted:

fiber mass fraction = (fiber volume fraction) x (fiber density) / [(fiber volume fraction) x (fiber density) + (matrix volume fraction) x (matrix density)]

• (0.3) x (2.6 g/cm^3) = 0.78 g/cm^3 [numerator]
• (0.3) x (2.6 g/cm^3) + (0.7) x (0.9 g/cm^3) = 1.41 g/cm^3 [denominator]
• 0.78 g/cm^3 / 1.41 g/cm^3 = 0.553 unitless

This would mean that the fibers contributes 55.3% of the total mass.

Therefore,

• The resin is 44.7% of the total mass (1-0.553 = 0.447)
• 100 kg resin / 0.447 = Total mass = 223.71 kg
• 55.3% of 223.71 = 123.7 kg fibers

This is unless of course my math is wrong, in which case my apologies.