Dear Aparecida,

If you made 1.0 L of this acid @ 16 mM, this means you would need

16 mMoles x 409.81 mG/mMole = 6557 mG in 1 L.

For 10 mL (0.01L), you would need 65.6 mG.

The density of chloroplatinic acid (CPA) is 2.43 g/mL = 2430 mG/mL.

The volume of CPA contining 65.6 mG is 65.5 mG/2430 mG/mL = 0.027 mL.

0.027 mL = 27 microliters.

If you add 27 uL of CPA to 10 mL of water, the CPA concentration is 16 mM.

I hope this information helps you.

Bill Colonna Dept. Food Science & Human Nutrition, Iowa State University, Ames, Iowa, USA [email protected]

Dear Colonna

I would like to thank you so promptly for your help.

Thanks!!