It is not clear how heat from the motors are conducted onto the 'conveyor strip'. Also, the material of the 'conveyor strip' is unknown.

Unfortunately, most electrical insulators are bad conductors of heat.

Friction between the copper strip and 'conveyor belt' will add to temperature increase depending on the friction power loss.

The direction of movement of conveyor has to be opposite to that of the sequence of copper strip touching the conveyor to effectively try to remove heat. this means if the conveyor is moving in clockwise direction, the sequence of copper strips touching the conveyor should be opposite. Otherwise, the portion of conveyor from where heat was just removed by a strip will move ahead and be touched by the next copper strip, resulting in only small further heat removal while the remaining portion of hot conveyor will not touch copper strip.

Basically, you are trying to make a discreet operating model of cooling by fluid flow.

Dear Sir,

At first thankyou very much for your response.

I would like to insist on some following points.

(1)the conveyor belt is made with rubber.

(2) the stripes are made with copper.

(3) the copper strip will connected with the machine for 3 to 5 seconds.

(4)I will take wood as an insulator.

(5) the conveyor belt will not move continuously as it will move after each 3 to 5 second.

(6)yes,the conveyor belt will move clockwise so the copper strip also.

(7) most important the copper strip will touch the machine (to dissipate the heat) not conveyor belt.

Each copper strip is separated with each other strip with insulator and also with conveyor belt.

It is not work like conventional heat sink as the copper strip will be connected with machine for 3to 5 seconds only so after absorbing the heat it will be removed and a new copper strip will be connected with machine .the removed strip will be cooled down after dissipating the heat and there is no need of fluid.

It is fluid less model.

First, I am assuming that the device drawn is intended to cool a separate machine, rather than itself. If that is incorrect you may want to edit the original question to clarify.

It looks like it is essentially the same as liquid cooling in concept, a moving repository for heat. Whether or not it will work will depend on the specifics, but the concept seems okay. You would need to know how much heat the machine you are cooling will generate, what the average temperature of the metal mini-heat sinks would be when it came into contact with the machine, how much heat would be transferred, etc.

I think you could make this work, but I don't know if you would end up with any advantages over a more conventional heat-sink. The movement of the belt would put a relatively cool piece of metal against the material every few seconds, and the temperature gradient would assist in cooling, but the real issue is how quickly you can move the energy away on average. Maybe I shouldn't be thinking of something big, but if you have space for this wouldn't you have space for a larger or more efficient heat sink?

In the end, it all comes down to your application. If the numbers work out and it looks better than a heat sink, and you can't use liquid cooling for some reason, this might work.

Keep in mind too that the motors of the device will also add heat that will need to dissipate somewhere.

Dear James Sir,

You are correct but motor will move only after 3 to 5 seconds only a little bit so no heat will be generated.

Each strip will be connected to Electric motor to cool down it or in other words if initial temperature of machine is 30 ° centrigrade then it will be remain 30° centigrade if it runs 2,3,45,.... Hours and so on.

There is an advantage of regarding energy consumption as it will consume 15 to 20 times less energy than heat sink.

If I coupled this device with a Electric motor then it will work in such way that if the initial temperature of Electric motor is 30° centigrade then it will remain 30° centigrade if motor runs 2,3,4,5 ....hours and so on.

It will work far better than heat sink.

Got your point.

The motor to be cooled is not shown in the diagram and the motors shown are for turning the belt.

So now the question boils down to how fast can you remove heat by conduction. That depends on the mass of the copper strip, its cross section along the direction of heat flow and time of contact.

Your idea is not wrong, but the question is how effective will this system be in reality. That requires further investigation on a prototype. One cannot just say that "it will work far better than heat sink". Heat sinks are generally air natural or forced air cooled. I dont know if your system uses natural air cooling or forced air cooling to remove the absorbed heat from the copper strips.

Best wishes.

Dear Biswas Sir,

Thankyou for your reply.

Sir, you are correct that I couldn't show the motor to be cooled down in the diagram.

The mass and cross section of copper strip can be solved easily through design .

Now time of contact.

Each copper strip will be in contact with the Electric motor upto 3 to 5 seconds and after that will be disconnect with Electric motor to make way to the second strip to connect with Electric motor.

In this way each strip will connect and disconnect turn by turn.

In that time the each strip will get sufficient time to be cooled down naturally.

There is no need of forced air cooling so energy consumption will be very very less in this model than Heat sink.

"It will work far better than heat sink"

Here are some points to support the above sentence.

(1) A heat sink will get started hot after some time even if we use forced air cooling as it is coupled with Electric motor but what if I replace this heat sink after each 3 to 5 seconds with second heat sink

And the second with third and third with fourth and so on....

I take 4 seconds time.

So if a single heat sink is permanently connect with Electric motor then after 60 seconds it will get hot too much .

But if this single heat sink is getting replaced by new one heat sink after each 4 second then it will be get less hot and so the Electric motor.

(2) Energy consumption will be less in it as the motor will move a little bit only after 3 to 5 second.

That is my point.

Thankyou again for your response.

I understand the idea in the following way_

- the copper stripes contact the machine to be cooled, when they are down

- they are heated by heat conduction

- they are transported upwards by the conveyor belt

- they cool down again (by convection and radiation)

Basically this will work, the questions arising are:

- efficiency of heat conduction (from machine to stripe)

- efficiency (and speed) of cooling of the stripes, when they are up

If you need to blow air to cool down the stripes again, you should blow it directly on the machine, which you want to cool down.

Dear Kalkert Sir,

The efficiency of heat conduction ( machine to copper strip) will be depend on mass and surface area of copper strip.

Efficiency of cooling of strip depend on how much it is hot??

Each strip will be connect only for 3 to 5 seconds so after absorbing the heat it will be disconnect to the Electric motor.

There is no need of blowing air to cool down the strip as the strip will be collected down naturally ( by convection and radiation)

If there are 20 copper stripes attached on the conveyor belt and each strip is coupled with the Electric motor upto 4 seconds then each strip will get 80 seconds to be cooled down.

But only 15 seconds sufficient to get cooled down as the each copper strip will be get hot very very less.

And so the Electric motor.

Your temperatures are probably too low for any significant thermal radiation cooling, leaving only convection to remove the heat from your copper masses. your efficiency will suffer because not all of your Copper is conducting heat away from the source at any time. I think you will find problems with getting a low thermal resistance contact with any easily moving assembly. A properly designed heat pipe comes to mind as a comparison standard for your heat flow calculations. A heat pipe may be 200 times the thermal conductivity of Copper. As the old guy in the ESI repair department always said, "One experiment is worth a thousand expert opinions."

Dear wormer Sir,

What I thought is that if I use a continuous water jet to cool the motor then the motor will remain cool so if I use the copper stripes then the same effect will be occured.

The heat is also depend on the mass and surface area of object.

If surface area islarge than it will take more time to get hot.

But you are correct that""One experiment is worth a thousand expert opinions."

You can calculate temperature rise if you know the power to be dissipated (watts) and the thermal resistance of the heat path (motor to heat-sink + heat-sink to ambient, in degrees/watt). I think your statement about a large surface area taking longer to get hot is incorrect. If the heat sink mass is larger it will take longer to get hot. If the surface area is larger, it will have a lower thermal resistance. The system steady-state (final) temperature will not depend on mass, but only power input and thermal resistance. The mass will only affect the time needed to reach steady state.

Dear wormer Sir,

You are correct that larger mass will take longer time to be get hot.

But please tell me if continuous flow of water works to cool down the motor and motor temperature is remain same then if I use the copper stripes instead of water jet then the temperature of motor will be remain same or not.

The water-cooled system depends on the heat capacity of water, the volume of the water per unit time, and the thermal resistance between the water and the motor, resulting in a temperature rise of the water stream. The cold water enters the system, warms up, and the exits the system, taking the heat with it. The motor temperature will reach some equilibrium temperature that is warmer than the water exit temperature. The water goes somewhere else to release the stored heat. To achieve the same temperature of the motor, the Copper heat sinks must absorb the same amount of heat energy as the water stream, and then move that heat energy to another location. Unless you have an infinite supply of copper (or a very long length of your conveyor belt), you may not be able to move the same quantity of heat as your water method.

Have you done any calculations to determine how much power needs to be dissipated? What is the rate of the water volume you are trying to replace with your new heat sink method, and what is the rise in temperature of the water? How far away do you need to move your stored heat (copper blocks) to avoid heating your motor ambient air?

Dear Wormer Sir,

I will not wait of motor to be getting hot.

a motor ' s initial temperature is 30° centigrade before it's rotate.

Now if it's start to rotate then a water jet also start immediately to flow for 4 seconds and after absorbing the heat the water exit so there will be no chance of increasing in temperature as temperature will be remain same as in 4 seconds the temperature will be increased very minimal ( in points).

For next 4 seconds the water jet again work to absorb the heat.

The same way the copper strip will work.because it will not give any chance to motor to be getting hot if is coupled with motor from initial point.

Though I don't have any calculations. if I put a pot on the stove and pour a water jet on it from starting point then it doesn't get hot.

It remains cool.

I will have to do work regarding the mass and surface area of copper strip that how much heat it will absorb in 4 seconds and how quickly it will be cooled down.