Reaction between 2-methylimidazole and Mn(NO3)2
We have directly synthesized Mn3O4 from the reaction between 2-methylimidazole (2-MI) and Mn(NO3)2 (MN) after drying of the precipitations.
Aqueous solution of 2-MI slowly added to aqueous solution MN, so, immediately we have brown solution indicated Mn3O4, and/or Mn(OH)2 and/or MnOOH in the solution (I am not sure about that), but after washing and drying powders in air at room temperature, we will have high crystalline pure Mn3O4.
Especial concentration of 2-MI only can produce the special amount of Mn3O4, so, with increasing of MN concentration we will have the same amount of powder, meaning that for sure 2-MI is already reduced and cannot produce more powder.
So what will be the reaction? What happens to 2-IM?
For your information:
pH for 2-MI is around 6-7 depends on the concentration, and for the Mn solution is about 5.
2-MI can produce MOF with other elements such as Zn, Co,..., but with Mn cannot, and the output of reaction is Mn3O4 after drying not MOF.
Thank you
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