What will be the ablation temperature of Cu and Al. If we estimate it from ClT+Ce'T2= Enthalpy of evaporation ( Where Cl- specific heat of lattice and Ce'- specific heat constant for electron) for Cu it is around 10,000 K and for Al it is around 13,000 K is it correct?
Your question is not very clear. If you want to estimate the temperature of the plasma just after the evaporation, this value is too low. The laser provide a very high power density. Part of this density is lost by thermal conductivity in the metal. This is not very important, because in the ns scale diffusion is too small. Part of the energy is used to evaporate the surface, which is relevant but not very high. The most important contribution is to produce and heat the plasma. In my old calculation I have estimated as early time temperature, values above 60000 K.
The plasma formed than cools down by expansion reaching temperatures around 10000 K. For higher temperature (at the beginning of the ablation) you cannot measure the spectrum because the continuum is too strong. You start to measure the spectra when the plasma reaches temperature around 5000-20000 K (depending on the plasma composition and environment pressure), when the electron density is decreased.
My question is at what surface temperature the material will start move away from the surface (ablation temperature). Plasma temperature is a different thing. And plasma temperature can vary from laser to laser and material.
In my previous answer I was pointing out that the temperature is not the relevant parameter, but the energy flux. The heated region evaporates almost instantaneously, losing part of the energy through conduction with the surface.
This phenomenon is similar to the explosion. The plasma expands more rapidly than the release of energy. Your question is related to the equilibrium of phase change, that is not the condition met in laser evaporation.