If I add 25 mL of 0.05 M NaOH with 25 mL 0.05 M HCl at room temperature, then what will be the grain size of the salt precipitate? Can I observe the precipitate visually? How can i remove salt from the solution (assume others tertiary ions also present in the solution) without filtration? Is there any way to prevent salt formation after mixing NaOH and HCl ?
Mr. Ullah,
The asnwer to this question can be found in any textbook devoted to ''Analytical chemistry'' (acid-base interactions).
The reaction is highly favorable. Strong base NaOH and strong acid HCl react to form weak acid H2O and weak base NaCl. The equilibrium lies far in this direction.
The way to alter equilibrium is to take advantage of Le Chatliers principle or lower temperature, etc. But in this case you are trying to prevent a favorable reaction from happening after mixing these two together.
I was a visiting professor in ChemDep of Texas A&M University in College Station. TAMU is a great place to learn chemistry. Your question really surprised me. This is the professional forum. Always do your own homework before asking questions. I recommended Bojidarka B. Ivanova answer
Greg Petruncio, I appreciate your insight on the reaction mechanism. My deep gratitude to Bojidarka B. Ivanova and Yurii V Geletii also for your input. I am looking over it. My question actually much related to prevention of most favorable reaction, either by reducing temperature or applying any other forces. I have other anions and cations present in the solution. Eventually I will precipitate ligand from those tertiary ions at room temperature, but i do not want to precipitate any NaCl salt along with the targeted ligand.
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