I am trying to utilize schiff base reaction for the formation of secondary amine by linking two polymers.
In my NMR, I can observe a very sharp peak of reasonable intensity at about 1.3 ppm.
How can i prove or develop understanding whether i get secondary amines or not?
thank you for this question dear colleague??????
you have seen a very sharp spike of reasonable intensity at about 1.3 ppm.thank's?????????????????
1-this confirms an secondary amine ??????????? it's peak of (NH).
2-the peak of (NH2) for primary amine it's in range of (6.5 ppm to 2.1ppm) way?????????????it's the solvent effect???????????????.
3-The peak of (NH) for secondry amine in the range of (5.4 ppm to 1.2 ppm) under effect of solvent.
4-The peak of the amine in general will be shielded under the effect of solvent or the method of synthesis.
thank's
draw the structure in chem draw and expect HNMR to know NH of sec amine of polymer appear what
You won´t have a Schiff base from the reaction involving secondary amine, but an enamine.
But, what deutered solvent did you use?
Further, a "simple" IR spectrum could give relevant you information.
Generally, if you see a peak sharp or broad around 4 - 5 ppm, it may show the presence of NH, provided OH group is absent
Hi
Simply, Chem draw can be a useful tool for these type of problem analysis. Just draw the structure and compare with your data.
Thanks
thanks for all your answers. I'll act as per your suggestion and will let know.
solvent is h20:d20:0.1NHCl=8:1:1
IR spectrum could give you a simple indication about your sec. amine. For the Chem Draw is not always give you the right assignment. It depens on the structure that you have for example I've made a polymer that has a sec, side group and the peak of this group was in around 7. ppm
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