This question may seem a bit basic, yet confusing for me. What is the impact of laminar assumption on NS equations? For instance, compressibility has an impact on the final form of the NS equations. (Density derivatives is zero in the equations)
Hi Reza. If you write the NS equation in terms of Reynolds Number, it would help to understand it better. This way you can make the term that multiply by Re as zero since for laminar flow we can assume Re quite low (approximately zero). Therefore, NS equation will be so simple for laminar flow case.
Hi Ali, Thanks for the reply. I believe this is true for the Stokes regime which is as special case of laminar. In Stocks flow regime the Reynolds is very small and it results in very negligible effect of inertia. But for laminar case the story is different. The inertia is no longer negligible. Think about a Reynolds of around 1000 inside a pipe. The flow is laminar.
You are right. Since I have been working on micro scale I mistook with stokes flow. For laminar flow there is no other assumtion but getting reid of turbulent fluctuations. Let me think more about it. I will let you know.
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