Amravati Singh
Because you're only starting with a few mg of reactants? Perhaps pyrolysis has removed most of your material in the CO2 and water products? Perhaps one can only get a low yield from this type of process? Perhaps it's the color of the sun cut flat (after Robert Zimmerman)? Why not contact the authors of the paper first before posting on RG?
You need a lot more details of what you are doing rather than 'I followed this paper and can't reproduce the results'... The latter statement is, unfortunately, all too common in modern science.
Alan F Rawle sir, firstly I had prepared a sample in grams, and also I m not questioning their procedure, maybe they r getting less product because they have not mentioned yield. I thought maybe something is missing in my case,
that why I asked. And also I want to know if there is some effect of pyrolysis condition.
Thank you
Dear Amravati Singh in addition to the questions raised by Alan F Rawle it needs to be asked how trustworthy this paper is. In my opinion, the material is not really well characterized. In the first step RhCl3·nH2O is treated with triphenylphosphine and melamine to give a precipitate. The authors do not provide any indication about the nature of this precipitate. What is the role of the melamine? What's the composition of this initially formed solid? Then this more or less unknown material is calcinated at 900 °V to give another ill-characterized solid. Under these conditions the triphenylphosphine could easily evaporate completely instead of forming a rhodium phosphide. What is the composition of this product? The authors claim that "C, O, N, P, and Rh were uniformly dispersed across the RhxP/PNC-m sample", but I cannot remember having seen an elemental analysis. Just presenting a few more or less pretty TEM etc. images is not really convincing. As a reviewer I would not have accepted this paper in its current form.
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