It is known that anions of lower charge density are more polarizable. For anions having the same charge, the larger anion is polarised to a greater extent (F– < Cl– < Br– < I–).
Then, is [TFSI]– or [PF6]–, the larger anion, much more polarizable than I–?
Hong-I Kim
Thank you for the reply, Dr. Sankari Manda
I'm sorry, but I don't understand well.
Since TFSI is a non-coordinating anion, does that mean that it is less polarizable than the Iodine anion, even though its molecular size is large?
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