Is it true that the solution to Schrödinger's equation is equal to the statistical weights of the object concerned?

We guess the short answer is yes, it does.

A striking answer to the above statement appears in limited mathematical integrations:

I= ∫ y dx from x=a to x=b, . . . . (1),

I=∫∫ W(x,y) dx dy from x=a to x=b and y=b to y=c. . . . . (2)

..etc..

Equations 1,2 can be calculated numerically and precisely via the transition chains of the matrix B[1] by applying the so-called statistical weights,

I{1D,7 nodes}=6 h /77(6*Y1 +11* Y2 + 14* Y3+15* Y4 +14* Y5 + 11*Y6 + 6*Y7). . . . (1*)

I{2.9 knots}= 9 h^2 /29.5

2.75 3.5 2.75

3.5 4.5 3.5

2.75 3.5 2.75

(Y11,Y12,Y13,Y21,Y22,Y23,Y31,Y32,Y3) .. . . (2*)

NOW,

the equations 1*,2* are exactly the numerical statistical solution for ψ(r)^2 in the time-independent Schrödinger PDE [1,2].

[1]Effective unconventional approach to statistical differentiation and statistical integration, Researchgate, IJISRT journal, November 2022.

[2] Cairo Solution Schrödinger Partial Differential Equation Techniques – Time Dependence, Researchgate, IJISRT journal, March 2024.

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