most of the publications reported that the cutting force generated during machining process are greater than the thrust force. why?
Hi,
Please review the following link: http://www.learnengineering.org/2013/01/cutting-force-analysis-merchant-circle.html
Regards!
Hello Dinesh,
Magnitude of cutting and thrust forces are a function of tool geometry (rake angle, included angle, edge radius etc) , cutting parameters and workipece and tool materials.
By decreasing rake angle or chip thickness or by increasing edge radius, it is possible to get higher thrust forces.
I think the question must be not like this, but ask which happen before at the same force magnitude? cutting (shear) or bearing?
Assume that you have a force magnitude (F),
If you use (F) for cutting, and the same (F) for bearing.
Then the cutting will happen before bearing.
Obviously you know why ..
Probably in many cases, the cutting force is greater than thrust force.
However I propose to you search papers here in RG about machining forces measurements. I know that there are many works about this task. Thus, if you want, you can made a statistical study with the found results.
I agree with Dinesh Setti.
At low depth of cut, ploughing and rubbing dominate over shearing phenomena. This leads to increase in the force in the radial (thrust) direction during cutting.
The low feed (say 0.04 mm/rev) can also show you the significant rise in thrust force.
Apart from this the nose radius of your cutting tool also plays an important role. For the same depth of cut the larger nose radius insert will provide more thrust force as compare to smaller nose radius insert.
The total force in turning or drilling is the sum of 4 forces : friction forces on rake & relief face and deformation ( cutting ) forces on rake & relief face.
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