Dear Friends,
I have got a redox couple with a reduction potential at 0.5786 V and an oxidation potential at 0.4622 V , using these values, How would I arrive at the number of electrons involved or transferred in the redox reaction ?
for reversible redox reaction the Ecathodic - Eanodic =0.0591/n, so n= no. of electron calculated can be easily found. but is there any such way for quasi-reversible redox reactions?
This link Maybe useful for you :
www.chemistry.wustl.edu/~coursedev/Online%20tutorials/Redox.htm
thank you Abdelkader Mohamed Elsayed
the link brief the basic of redox reaction, finding the oxidation number of ions involved in redox reaction and balancing equation
but the doubt is how to understand an unknown redox reaction, with the help of Number of electrons involved in the reaction and the only data available is CV data obtained in two electrode method
You can't. You have to know what the reactions are, you can't calculate the number of electrons when you only know the potentials. The cell potential is related to the Gibbs Free Energy, G=-nFE where n is the number of electrons, G is the free energy, E is the voltage, and F is the Faraday constant
yes its true Stephen Cain
but i wonder how do we actually characterize an unknown elctrochemical reaction from its redox potentials?!
If the redox potential is the only information that you have, you really cannot say much about the chemical reaction. For example, suppose I told you that a reaction has a Gibbs standard free energy of -10 Kcal/mole, what could you tell me about the reactants? Essentially nothing other than they spontaneously react to the tune of 10Kcal. You can't tell me what the reactants are, how fast the reaction proceeds, if there is a thermal barrier to the reaction, and so forth. In short, you need a lot more information. A good starting point would be an elemental analysis to see what species are present.