Yes, if the oxidation products A(+) is unstable.
A - e = A(+)
A(+) -> product
Yes, if the oxidation products A(+) is unstable.
A - e = A(+)
A(+) -> product
With the potential you have in mind it is one electron redox process. Quasi reversible is a vague term. If the diffusion current is properly managed and one apply fast scan for better and quick electron response then a redox reaction may show reversibility which under slow scan may show larger separation of peak potentials. Under the scan time if the concentration of both the species ( reduced and generated oxidized or vice versa) remain the same ( theoretically it should be so for a reversible reaction ) then that ratio will be unity. If the generated redox species is rapidly drifted from the double layer ( present at the tip of the electrode ) then the said ratio may deviate. Further if the generated redox species responds to further chemical reaction within the time scale of the CV scan then also the ratio may change and as narrated by Dr Geletii if that generated species is unstable within the scan time then also it will deviate from the ratio unity
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