This is not always true and depends on many factors such as surface reaction and .... But in general, peak shifts against scanning rate changes are related to the transfer of electrons from the electroactive species to the electrode surface and vice versa.
When increasing the scanning speed, we may not allow the intermediate stages of the reaction to appear, especially the chemical stages, and thus move to the last stage quickly. Therefore, when studying any compound, weak scanning speeds must be applied to know the true speed of the reaction, and therefore this affects the value of the electric potential difference. Thanks
It is mostly due to high mass transfer rates. Detailed explanation is given here. https://chem.libretexts.org/Courses/University_of_California_Davis/UCD_Chem_115_Lab_Manual/Lab_1%3A_Cyclic_Voltammetry