P-25 give better results as compare to mesoporous TiO2 without loading any cocatalyst even recombination rate for mesoporous TiO2 is less as compare to P-25. Although it may be not that much crystalline as P-25, but what are the parameter responsible any pure anatase phase system without loading co catalysts. P-25 giving more better results. Can any body guide why it is happening in case of water splitting. In degradation reaction P-25 shows less active than m-TiO2 that is due to Surface Area . Can Any justify it for Water splitting?
In general Anatase phase its better than rutile for photocatalysis, but some kind of mixture, near to P25, its better than anatase pure, this synergetic effect its maybe for the lower band gap for rutile which permit e better solar energy harvesting.
Agree with the above answer, in P25 it has both rutile and anatase phase, so because of less bang gap in rutile it absorbs more light. And maybe even though recombination is more, generation of electron is also more. In case of mesoporous TiO2, light absorption and generation of electron is less compared to P25. May be this will help bit.
I am surprised this works without a cocatyst. Do you have any idea about the quantum efficiency of your system?
There is a view that P25 works well because the mix of anatase and rutile behaves like a photodiode leading to better charge separation at the rutile/anatase interface but there can be many reasons why materials show low efficiencies, charge recombination, charge trapping, low surface area.
This is not the splitting of water, but the very well known photoinduced dehydrogenation of methanol
the evolution of Hydrogen is low as compare to complete methanol reforming but without loading cocatalyst how someone can prove it that we are not getting hydrogen from water its coming only from methanol some literature Proves after loading cocatalysts even we will get less h2 compare to complete reforming of methanol.
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