How can I calculate hydropower plant production (GWh) when the current production is given 30GWh and environmental spill is 3m3/s, discharge is 40m3/s?
Hello Omar, thank you so much for so many interesting and valuable articles and links. However, I could not find any data about the spill and the relation to the calculation question I do have. I want to know the method or formula of calculating the data I have provided above
The calculation sheet here https://www.engineeringtoolbox.com/hydropower-d_1359.html that Omar suggested includes all the key variables that you need. You cannot calculate hydropower plant production just from the variables you quote in your question. You'll need the following:
- Height through which the water falls (the head) (H)
- The overall efficiency of a hydopower plant (e.g. turbine efficiency etc) - typically between 75% (0.87) and 95% (0.95) (eta)
- The density of water (rho) = 1,000 kg/m3
- Acceleration due to gravity (g) = 9.81 m/s2
- The average flow through the turbines Q in m3/s
You can then calculate the power P generated in Watts (W) using:
P = H x eta x rho x g x Q
If you want to know the amount of Watt Hours your hydropower plant will produce you'll need to know how many hours it will be running for over a particular period of time, You will also need to take into account that, depending on the arrangement of the scheme, the flow (Q) can vary considerably during the year or season.
What you need to know is the flow (Q) going through the turbine. In your question you state that the environmental spill is 3m3/s and discharge is 40m3/s. It is not clear if you have 40 m3/s going through the turbine AND 3 m3/s for an environmental compenstion flow or 40 m3/s in total i.e . 37 m3/s going through the turbine and 3 m3/s as an environmental flow.
There is plenty of information on line on how to estimate hydropower power production as Omar pointed out.