Take “ln” on both sides of the equation. Then your equation would be ln(Mt/Mi) = ln (k) + n*ln (t).
The plot the graph for ln (Mt/Mi) versur ln (t). Slope of that equation is “n”
Mt/Mi is the fraction of drug released at time t over the total amount of drug released. To plot your data according to Korsmeyer-Peppas model, you should only fit values up to Mt/Mi=0.6.
You can refer to this paper, it is really helpful to guide you through the different release kinetics models and how to interpret your results.
http://www.sciencedirect.com/science/article/pii/S0928098701000951
Agree with Mohamed Aboughaly.
You should follow the above-stated paper for further explanation.
Take “ln” on both sides of the equation. Then your equation would be ln(Mt/Mi) = ln (k) + n*ln (t).
The plot the graph for ln (Mt/Mi) versur ln (t). Slope of that equation is “n”
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