The farmers submitted a soil sample to the laboratory for soil analysis. Base on
the results, the soil analyst come up with the recommendation rate of 90-60-30 kg %N,
P2O5, K2O per hectares. Given the following fertilizer materials (complete 14-14-14), Di-
ammonium phosphate (18-46-0) and urea (46-0-0), compute the amount of fertilizer
materials needed to satisfy the recommended rate.
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To calculate the amount of each fertilizer material needed to satisfy the recommended rate, you can use the following formula:
Amount of fertilizer material (kg) = Recommended rate (kg)/Percentage of nutrient in fertilizer material *100
Let's calculate the amounts needed for each nutrient:
1. For Nitrogen (N):
Amount of urea} = 90/46*100
Amount of urea approx 195.65 kg
2. For Phosphorus (P2O5):
Amount of diammonium phosphate (DAP) = 60/18*100
Amount of DAPapprox 333.33 kg
3. For Potassium (K2O):
Amount of complete 14-14-14 = 30/14} *100
Amount of complete 14-14-14 approx 214.29 kg
So, the recommended amounts of each fertilizer material are approximately as follows:
- Urea: 195.65 kg
- Diammonium phosphate (DAP): 333.33 kg
- Complete 14-14-14: 214.29 kg
It is essential that Mr. Singh and Freire also comment on how much nitrogen and phosphorus is usually taken up by the crop vs how much is usually washed into streams, waterways, lakes and oceans, and approximately how much environmental damage is caused by that...
First we need to calculate for potassium and then for the rest!
# Because it is in the separate package @! And then diduct the amount of N and p which is in pack with k and then we can Add N and p separately
For exampl