First of all I need to know the molarity of my H2O2 solution. For this I will need the density of H2O2 which is 1.11kg/L or 1111 g/L. this means that m = 1111* 0.3 (30%) = 333.3 g in 1 liter of solution.
n = m/M.
M of H2O2= 34.01g/mol
so n = 333.3/34.01 = 9.80 mol/L. So your solution is 9.80 M.
Then, to prepare a 75 µM solution you dilute the solution which is 9.80 M using the rule CiVi = CfVf
H2O2 is unstable and is frequently sold (in a fresh bottle) at a little greater than the strength disclosed on the label to allow for decay (the vented cap is to stop older bottles from exploding due to oxygen gas buildup. I used this method:- H202 were prepared daily from serial dilutions of a known concentration assuming an extinction coefficient of 81 M -1 cm -1 at 230 nm. Reference for the extinction coefficient of H2O2 at 230 nm is:-
Homan-Muller, J.W.T., Weening, R.S. and Roos, D. (1975) Production of hydrogen peroxide by phagocytizing human granulocytes. J. Lab. Clin. Med. 85, 198--207.
More details of this method ,and other methods for determining H2O2 levels (and necessary precautions required for accuracy when using hyper-sensitive fluorescent H2O2 assays) can be found in my PhD thesis
Thesis Nitrofurazone and Hydrogen Peroxide Metabolism in Trypanosoma brucei.
and in some of my related publications from the mid-late 1980s.