Temperature of a gas is measured in electron Volt. But I don't know how this is converted . Please help me understand.
You can follow
https://en.wikipedia.org/wiki/Boltzmann_constant
https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units#Kelvin
These numbers do not take into account the 2019 redefinition of the SI base units. For this, consult:
https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units
The energy E in joule (J) associated with the temperature T in kelvin (K) is equal to kBT, where kB is the constant of Boltzmann [1,2]. Now, 1eV = (e/C) J, where e/C ≡ {e} is the absolute value of the charge of an electron in coulomb (C = A s = ampère × second). These bring one to [3]:
1 eV = 1.602 177 33 × 10-19 J = 11 604.45 K.
Thus, 1 eV is approximately equal to 104 K, or 1 K approximately equal to 10-4 eV.
[1] https://en.wikipedia.org/wiki/Boltzmann_constant
[2] https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units#Kelvin
[3] These numbers do not take into account the 2019 redefinition of the SI base units. For this, consult:
https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units
Respected Farid Sir
Thank you for adding such a valuable ans. So ,does it mean that a approximately 1 ev energy of a particle means approximately 10,000 degree Kelvin ?
Actually, we know that the photons in the visible range carry few eV energy.
But what about the temperature of such a photon gas ?
Regards
Nityananda Das
Nityananda Das :My pleasure. As for your first question, the answer is in the positive (my last sentence in my previous comment on this page conveys the same thing).
Regarding your last question, temperature T is a thermodynamic parameter associated with a system in thermal equilibrium. Depending on which thermodynamic potential one uses, T may or may not be a thermodynamic variable. The internal energy E = E(S,V,N) of a system in thermal equilibrium (with S = entropy, V = volume, and N = number of particles) is not an explicit function of T; E only implicitly depends on T through the temperature dependence of S. In contrast, the Helmholtz free energy F = F(T,V,N) = E - TS is an explicit function of T. In short, temperature of a system in thermal equilibrium is not equal to its energy divided by the Boltzmann constant; a given amount of energy can however be expressed (as a matter of convenience) in terms of some effective temperature (which is to be distinguished from the T just discussed) in units of the Boltzmann constant.
You can follow
https://en.wikipedia.org/wiki/Boltzmann_constant
https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units#Kelvin
These numbers do not take into account the 2019 redefinition of the SI base units. For this, consult:
https://en.wikipedia.org/wiki/2019_redefinition_of_the_SI_base_units
I don't think you'd ever state the temperature of a gas in eV. Technically there is no way to do this conversion, it's converting apples to oranges.
See the top answer here for the technical reason:
https://physics.stackexchange.com/questions/231017/is-the-boltzmann-constant-really-that-important/231065
e= electron charge
kB boltzmann constant
Te {kelvin]= Te{eV} * e / (1.5 * kB)
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