I have got a publication in which the authors prepared BaFe12O19/CoFe2O4. But the amount / concentration used for preparing the metal nitrate solutions were not mentioned in the publication (except mentioning 'stoichiometric ratio')in Materials and methods section.
Please give your ideas about how to find the weight and concentration of the chemicals used in the synthesis from paper. Attaching the full paper with this question.
Reference:
Yang H, Liu M, Lin Y, Yang Y. Simultaneous enhancements of remanence and (BH) max in BaFe12O19/CoFe2O4 nanocomposite powders. Journal of Alloys and Compounds. 2015 May 15;631:335-9.
1. Why not write the communicating author for details? Sure they will be responding.
2. Use 1:1:1. w/w, and report your result.
For example the compound (BaFe12O19) Is composed of one mole of BaO plus 6 moles of Fe2O3 So you can calculate how many gram of BaO you need from its raw material that is Ba(NO3)2 in such case to prepare 100 ml solution contains 1 molar of BaO using the following equation Wt = (M* V * M.wt)/1000
where: Wt = weight of Ba(NO3)2 needed to prepare the one molar solution of BaO
M= Molarity needed for the solution
V= the volume in ml (Cm3) of the solution that is in this example = 100ml
M.Wt= Molecular weight of Ba(NO3)2 and it equals to 261.34
By applying in the equation Wt = (1* 100 * 261.34) / 1000
hence the weight needed from Ba(NO3)2 is equals to 26.34 gram .
By the same way you can calculate the weight of Fe2O3 from its raw material that is here Fe(NO3)3⋅9H2O but remember you will need to prepare 6 molar solution
because the ratio between BaO and Fe2O3 in the compound is 1 : 6 as explained above .
you can apply the above equation to prepare any concentrations of the solution for any compound.
Regards
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