I used the chlorophyll fluorescence measurement using PSI Fluorometer, range of light is 455 nm and get the measurement:
"type":"ojip",
"fo":133,
"fj":141,
"fi":144,
"fm":143,
"fv":10,
"vj":0.800,
"vi":1.100,
"fm/fo":1.075,
"fv/fo":0.075,
"fv/fm":0.070,
"mo":3.600,
"area":35458,
"fixarea":141076,
"hacharea":8082,
"sm":3545.780,
"ss":0.222,
"n":15956.011,
"phi_po":0.070,
"psi_o":0.200,
"phi_eo":0.014,
"phi_do":0.930,
"phi_pav":985.437,
"pi_abs":0.000,
"abs/rc":64.350,
"tro/rc":4.500,
"eto/rc":0.900,
"dio/rc":59.850,
"type":"flash",
"wavelength":455,
"percent":30,
"intensity":nan.0,
"type":"super",
"wavelength":455,
"percent":50,
"intensity":nan.0,
"type":"actinic",
"wavelength":455,
"percent":10,
"intensity":100.0,
"description":""
So, I wish to know how i will find out how much ATP produced in this measurement to understand the use of Chlorophyll fluorescence.
The short version is that you shouldn't try to calculate ATP produced from a measurement of chlorophyll fluorescence. To do so would require a series of assumptions about the ratio of LEF:CEF, PSII:PSI, and the degree of shunting of electrons to molecular O2. All of which would require more and better measurements.
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