04 April 2019 11 342 Report

Hi,

I'm looking for the proper way to analyze some of my data.

I studied predation in fish, by looking at survival rates of different groups of larval fishes when facing predators.

In the first trial of the experiment, I put 10 larval fishes of the group A, 10 larval fishes of the group B, and 10 larval fishes of the group C, all together in a predation arena.

After 2 hours:

Group A had 10 survivors

Group B had 8 survivors

Group C had 6 survivors

In the second trial, same procedure.

Group A had 5 survivors

Group B had 4 survivors

Group C had 3 survivors

etc, multiple times.

The issue here is that predators are sometimes very hungry (see the second trial) and sometimes not that much (see thr first trial) so calculating a "survival mean" for each group, among all the trials, makes no sense to me (lot of variability).

So what I did is calculating the "overall survival rate" in each trial.

Overall survival in trial 1 : 0.8

Overall survival in trial 2 : 0.4

Then I substracted this "overall survival" to each group survival, in order to create some sort of an index that "normalizes" each survival rate according to the "overall predation" in each trial.

So this gives me the following:

In the 1st trial

Group A survival index = 1 - 0.8 = 0.2

Group B survival index = 0.8 - 0.8 = 0

Group C survival index = 0.6 - 0.8 = -0.2

In the second trial

Group A survival index = 0.5 - 0.4 = 0.1

Group B survival index = 0.4 - 0.4 = 0

Group C survival index = 0.3 - 0.4 = -0.1

So when I calculate the mean of these indexes for each fish groups among all the trials, I end up with something nice : group A survival index is always positive, group B around 0, and group C always negative, so low variability and nice means that suggest that group A survived more than group B, and group B survived more than group C.

But now I would like to test this statistically, and I can't find out how to compare multiple paired data of that type. I usually do my stats in R.

If anyone has suggestions I'll be more than happy.

Thank you very much for those who read me up to here, and thanks in advance for those who'll be able to help :)

Cheers

Marc

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