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This question was proposed on Physic StackExchange yesterday (https://physics.stackexchange.com/questions/830965/how-to-determine-the-alpha-value-of-artificial-viscosity-in-smoothed-particle-hy), but was closed today because it deals more with engineering instead of physics, and is thus off-topic. So I propose it here and hope someone may help me explain it.
I am confused about how to choose an appropriate value of $\alpha$ in the artificial viscosity. The value that I deduced is far from the recommended value and led to great numerical instability.
Artificial viscosity is introduced into the momentum equation of smoothed particle hydrodynamics:
$$\Pi_{ij}=-\alpha h\frac{c_i+c_j}{\rho_i+\rho_j}\frac{\boldsymbol{v}_{ij}\cdot\boldsymbol{r}_{ij}}{{r_{ij}}^2+\epsilon h^2},$$
where $\alpha$ is a dimensionless factor, $h$ is SPH kernel radius and $c$ is the speed of sound. The artificial viscosity is related to the physical dynamic viscosity (Pa*s) by
$$\mu=\frac{\rho\alpha hc}{8}$$
for two-dimensional cases [1]. Hence, if the values of $h$, $c$ and $\mu$ are given, we can estimate the value of $\alpha$ as
$$\alpha=\frac{8\mu}{\rho hc}.$$
When it comes to the sound of speed, in order to both limit the density variation within 1% ($\delta\rho/\rho\sim v^2/c^2$) and allow an acceptable timestep (by the CFL condition), $c$ is also artificial, and customary to be $10v_\mathrm{max}$, where $v_\mathrm{max}$ is the maximal fluid velocity [2,3]. As to the case of dam break with the initial water column height of $H_0$, the estimate of $v_\mathrm{max}$ is
$$v_\mathrm{max}=\sqrt{2gH_0}.$$
So Monaghan set $c$ as $\sqrt{200gH_0}$ in [2].
Assume the initial spacing between fluid particles is $H_0/N$, and the SPH kernel radius is triple the spacing,
$$h=3\frac{H_0}{N}.$$
Now we may obtain a proper value of $\alpha$:
$$\alpha=\frac{8\mu}{\rho\cdot(3H_0/N)\cdot 10\sqrt{2gH_0}}=\frac{2\sqrt{2}}{15}\frac{\mu N}{\rho\sqrt{gH_0^3}}$$
In the case of dam break, one can assume that $\mu=1\times 10^{-3}~\mathrm{Pa\cdot s}$ (water), $\rho=1000~\mathrm{kg/m^3}$, $100\leq N\leq 1000$, $0.1~\mathrm{m}\leq H_0 \leq 1~\mathrm{m}$, $g=9.81~\mathrm{m/s^2}$, and we may estimate that
$$6\times10^{-6}\leq\alpha\leq2\times10^{-3}.$$
This is way too far from the recommended range of $\alpha$ which is 0.01-1.
And when I used the estimated alpha value to simulate the dam break, it could not converge as expected. **So, I wonder whether there is any mistake in my estimation, or any misunderstanding of the SPH theory.** Any comments or advice will be appreciated!
**References**
[1] Monaghan, J. J. Smoothed particle hydrodynamics. Rep. Prog. Phys. 68, 1703–1759 (2005).
[2] Monaghan, J. J. Simulating Free Surface Flows with SPH. Journal of Computational Physics 110, 399–406 (1994).
[3] Monaghan, J. J. Smoothed Particle Hydrodynamics and Its Diverse Applications. Annual Review of Fluid Mechanics 44, 323–346 (2012).