My question is about how to calculate the current density. for example, If I used a two-electrode cell containing one Ni foam electrode of 0.5 cm2 as the working electrode and the other Ni foam electrode of 0.5 cm2 (the same surface area) as both counter and reference. I used this system to measure the linear sweep voltammetry (LSV) for overall water splitting (current (mA) versus potential) I want to convert the plot to be (Current density (mA/cm2) versus potential). Do I divide the current (mA) by 0.5 cm2 (surface area of one electrode) or by (2*0.5) cm2 (total surface areas of the two electrodes)
It is the same current going through each of the electrodes. The current density though can be different if the surface area of electrode is different. This is not the case in the configuration that you are using : the current density at each of your electrodes is j_a = j_c = I/A, where I is the current going through cathode and anode, and A is the surface area of each of these electrodes.
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