The sterilization dose for Streptococcus lactis bacteria is 88 J/m2. If a “germicidal” UV lamp, λ = 254 nm, is specified, and will be located at a distance of 0.1 m from the bacteria,
what power light is needed, assuming an isotropic point source?
Consider or assume an area element at the 10cm distance.
Calculate the dose there. Including a certain exposition time this gives irradiance.
Calculate its solid angle of the area element seen from the point source and you'll get radiant intensity. Radiant intensity times solid angle of the full hemisphere gives the necessary energy of the source.
The whole thing is called the inverse square law of radiometry.
Henning Rehn I have studied these theories in books. That's a primary reading from a good book. You might have noticed that I reproduced an entire question here. I expect a complete solution in return.
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