hi,

Since the droplet starts from the rest and accelerated under gravitational acceleration, newton's second law should provide (approximate) an adequate result.

Regards

Dear Rizwan,

If we consider an inviscid flow then the impact velocity is simply given as

u = sqrt(u1*u1+2*g*h)

where, u1= drop velocity at nozzle exit and h = distance of the nozzle exit from the plate along the gravity.

If we consider the droplet in viscous flow the you need to solve a non-linear differential equation given below.

mudu/dx = mg - Fd,

where Fd = drag force = Cd*A*0.5*rho*u*u