Since density of steel fibre is 7900 kg/m3. Volume of steel fibre 1% i.e. 0.01. So mass of steel fibre is 7900 x 0.01 = 79 kg/m3

For more detail please refer any standard code for mix design such as ACI 211.1-91, EN 206, IS 10262 etc.

The amount of fibres is expressed as a fraction of the concrete volume. So, if it is 1%, and you want to calculate its weight per m3, you'll only have to multiply the fibres' density by 0.01; as Shashikant Kumarr said.

Generally fibres we add by percentage of the volume of cement or by the weight of cement e.g for 500 kg cement require per cum then 1%*500=5 kg

0.01*1*7800=78 kg per 1 m3 of concrete

Hello ,, 1% by volume of steel fiber can be calculated by needing density of steel fiber itself only , if steel fiber with 7850 kg per cubic meter then you need

0.01* 7850 = 78.5 kg for each 1 cubic meter of concrete

with best wishes -- so you first check the density of steel fiber it ranged from about 7800 to 7890 kg per cubic meter.... thanks

The density of steel fiber is about 7860 kg/m3. So that if the fiber fraction is 0.25%, this means that the weight of fiber required equals to 20 kg. This results came from the following formula: Weight of fiber = 0.25% * 7860. Hopes this is useful.

The density of these fibers (steel fiber density is about 7860) must be taken into account in order to be able to calculate its volume.

Greetings! Regarding your question, 1% by volume of steel fiber can be calculated through the density of steel fiber per se. If steel fiber with 7850 kg per cubic meter, then you need 78.5 kg steel fiber for every cubic meter of concrete.

I hope the following is helpful.

Kindky refer pg:13 of IRC SP-46