I have restored the isosceles triangle (see attached figure). Its shape is restored with the next pairs of (x ; y): (0 ; 0) (40 ; 4) (80 ; 8) (100 ; 10) (120 ; 8) (160 ; 4) (200 ; 0)

Now I want to calculate the curvature for central point of (100 ; 10). I apply the concept used in ArcGIS (see another attached figure). During calculations I assume that E=0 (isolated ridge for which elevation changes only along single direction).

Thus, the calculation results for Lp=20;60;100 m are the next:

for Lp=20 m: Curv=(-200)*(0.5*(8+8)-10)/202=1.00

for Lp=60 m: Curv=(-200)*(0.5*(4+4)-10)/602=0.33

for Lp=100 m: Curv=(-200)*(0.5*(0+0)-10)/1002=0.20

As it can be ssen, Curv value is strongly determined by Lp, even if the shape of analysed topography does not change. Can somebody explain me this discrepancy in more details or reccomend some references for further reading?

Thank you in advance,

Almaz

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