If i assume to remove an electron from the HOMO of my metal oxide, the energy of an electron can be calculated from the UV. However, the similar case can I assume the same in electrochemical system? If yes, what are the energy differences for the same electron in optical and electrochemical system?
read this it will help you :
http://plasticphotovoltaics.org/lc/characterization/lc-advanced-c/lc-uvvis.html
https://www.osti.gov/scitech/servlets/purl/629305
1. ChemPhysChem 9, 2574-2579, Dec. 2008,
2. A. Franceschetti, A. Zunger, Phys. Rev. B 2000, 62, 2614–2623
http://www.sciencedirect.com/science/article/pii/001346869400317T
http://physics.ucsc.edu/~sacarter/HoltJCP2005.pdf
https://en.wikibooks.org/wiki/Introduction_to_Inorganic_Chemistry/Basic_Science_of_Nanomaterials
Dear Natarajan,
before I can comment, you have to be much more clear in your question :
1. What is HOMO ?
2. What is UV (ultra violet frequency range ?)
4. How do you define your metal oxide system and how do you define your electrochemical system ?
If your metal oxide system and your electrochemical system are the same, then there is no difference in the energy of electron in the bulk of your system. The quantum energy levels are calculated through Schrodinger equation and the (electro)chemical potential follows directly from this spectrum.
But I might have misunderstood something.
With best regards
Petr
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