Dear Katerina Tsiko thank you for posting this interesting technical question on RG. Sodium tungstate can be easily prepared in the lab by dissolving either WO3 or tungstic acid in the calculated amount of aqueous sodium hydroxide:

WO3 + 2 NaOH = Na2WO4 + H2O

You can use a slight excess of WO3 in order to make sure that the NaOH is completely neutralized. Then remove the unreacted WO3 by filtration through a folded filter and evaporate the clear filtrate to dryness.

Good luck with your work and best wishes, Frank Edelmann.

P.S. You can also edit your question and replace the wrong term "sodium tungsten" by the correct term "sodium tungstate". Just click on the down arrow next to "Share" and then click on "Edit".

Hello,

When you add a NaOH to NH4WO4 the following reaction occures:

NH4WO4 + NaOH = Na2WO4 + NH3 + H2O

and the NH3 is eliminated from the rection solution to the gas phase (air).

So the reaction should be done in ventillated box so not to be poisonned by NH3.

After partial eveporation and cooling the reaction glass the Na2WO4 crystalls will be formed

Konstantin E. German Frank T. Edelmann Hello

Is it formed wo3 in the following reactions?What are the products of these reactions?

1) Na2WO4+NaOH=???

2) Na2wo4+NaOH+HCl=????

it is synthesized WO3 in the basic environment under hydrothermal conditions??

Thank you if you guide me

Vadim S. Gorshkov