Generally, the resistance depends upon the resistivity, length and cross section area of the specimen. Because the resistance is proportional to length of the sample. As we decreases the thickness of the sample then obviously its length for charge transport will be changed therefore the resistance would declined.
In general, the material’s sheet resistivity, r, can be calculated by the relation
r=RCF(V measured /I measured).
The resistivity correction factor RCF takes the size of the test structure, the thickness of the material, the size of the electrodes, and the position of the electrodes with respect to the boundary of the test structure into account. So, if the thickness is more charge transport will change, which will affect resistivity.
1. the 4-probe measurements of dc resistance are only precise enough for materials with resistivities bellow 800 Ohm.cm (given a typical dimensions like thickness < 1-3 mm and probe separation ~5 mm.
2. if the separation between the electrodes is >> thickness of the material, then in the first approximation, the resistance should increase by a factor of two, whent the thickness is decreased by a factor of two. The resistance of your sample in this approximation is R~resitivity. (voltage probes separation)/(thickness of the pellet).
3. Please consult the following :
Semiconductor Material Device Characterisation by D.K.Schroder (Wiley 1998)