I really need to know the relationship between Li2MnO3 (lithium rich layered oxide) and the conventional layered oxide (LiMO2). I want to prepare Li2MnO3 and i need to know the stoichiometric amount of the metals to introduce.
Thanks
Li(Li1/3Mn2/3]O2 = Li4/3Mn2/3O2 = (Li2MnO3)*2/3
The formula Li2MnO3 is used as a simplest representation of stoichiometry. Li(Li1/3Mn2/3]O2 better represents the crystal structure of Li2MnO3: it can be derived from the LiMO2 structure by substitution of 1/3 of the ions in M positions by Li.
Thanks Alexander. If i understand your answer very well, it means Li2MnO3 is the stoichiometry but that the structural representation is Li(Li1/3Mn2/3]O2. But in preparing the compound, will the mole ratio of Li:Mn be set as 2:1.
The confusion in your response: Li2MnO3 can be derived from the LiMO2 structure by substitution of 1/3 of the ions in M positions by Li.
In this case the mole ratio of M in LiMO2 is 1 so substituting 1/3 of the ions in M positions by Li will give the mole ratio of Li in the compound as 1.1/3 which is not equals to the mole ratio of 2 for Li in Li2MnO3.
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