I am cleaning biochar with DI water.
For me to prove that my biochar is already clean, I subject it to UV-Vis at 254 nm. Sometimes 274nm, 284nm. The result should be 0.00.
But my prof said I should use 254nm.
I just wonder why at 254nm?
I've searched a lot on google but nobody can specifically explain this so I wrote down my qusetion here. Hope somebody can answer it in simplest terms. Thank you!
Hazel Anne Cledera
You should have written the question differently. After cleaning the biochar with water, I take the UV spectrum of the biochar and check its purity by the absence of absorption intensity at 274 nm, 284 nm. The professor knows that the impurity in biochar should absorb at 254 nm. Therefore, the professor asked you to check this absorption band of electromagnetic radiation for some substance. This is usually the total absorption of aromatic hydrocarbons.
To implement the UV method, a spectrophotometer of any model that provides measurements in the UV region of the spectrum can be used. The UV index (A254) is measured at a wavelength of 254 nm in a quartz cuvette with a layer thickness of 10 mm. Distilled water is used as a reference solution. Determination duration 5 - 10 minutes. This technique is used to analyze wastewater.
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