All this time, people thought that dQ was not a complete differential, but dQ/T was considered as a complete differential.
However, this is wrong.
The facts are just the opposite: dQ is actually a complete differential, but dQ/T is meaningless.
in ΔQ/T, the relationship of Q and T is the ratio of ΔQ and T or the product of 1/T and ΔQ, so, in ΔQ/T, Q and T can be any relationship.
But in dQ/T, the relationship of Q and T is not the ratio of dQ and T or the product of 1/T and dQ, but the relationship to Find the Original Function of 1/T in dQ/T=1/TdQ.
For we know Q is not a single-valued function of T, (in fact, Q=f(P, V, T) ), so, ΔQ/T can NOT turn into dQ/T, or say, dQ/T is meaningless.
The problem is not whether dQ is meaningful or not here, it is 1/TdQ is meaningless !
Q = f(T, V, P) is a process quantity which varies with path, it has innumerable forms between the same original and terminal states, and has a unique form for fixed reversible process path. When the given path is fixed, Q = f(T, V, P) is the system state variable.
So, dQ=df(T, V, P) is a perfect differential, it is meaningful;
but the integral variable of 1/TdQ is self-contradictory (T and T, V, P), so, 1/TdQ=1/Tdf(T, V, P) is meaningless, that is ∫T 1/TdQ = ∫T 1/Tdf(T, V, P) is not a meaningful integral, or say, it is not a integral at all.