The ABTS•+ radical cation was produced by reacting 7.4 mM ABTS and 2.6 mM potassium persulfate solutions (1:1) and stored in the dark at room temperature for 12 h and then diluting with methanol to get an absorbance of 1.1 ± 0.02 at 734 nm. Plant extracts (150µl) at 200µg/ml was mixed with ABTS•+ solution (2850 µl) and then incubated at dark for 2 hr. Absorbance was found to be 0.218 at 734nm. Trolox standard is prepared from 50 to 600µM. The equation of trolox is y = -0.0010x + 0.6713, R2 = 0.9968. Most of the paper followed in the Re et al (1999) was expressed in % inhibition or IC50 or trolox equivalent and its ABTS•+ solution was diluted to 0.7 absorbance. But I don’t find any paper expressed in % inhibition for the protocol which I have followed. Can it express in % inhibition using the same protocol or it should express as µM TE/g? If it should express in trolox equaivalent, then how can it calculate? Please help me