Suppose that e-h pairs are generated on anode surface of an insulator by surface absorption of light. some of the electrons recombine there in surface very shortly. The remaining electrons are pulled out of the insulator by the positive anode. Now the remaining holes start their journey towards cathode.

Books and papers say, the holes recombine with electrons/get trapped in defects and so their density decreases as they move forward. In a paper "High Field Effects in Photoconducitng Cadmium Sulfide" by Many, the hole density in steady state is given as  

p(z)=(Gs/(mu*E+Sp)*exp(-x/mu*t*E)

Which clearly shows that the hole density decreases exponentially with the thickness (x) of the insulator.

  • The situation becomes confusing to me (probably I am not thinking correctly) when the cathode can not inject electrons into conduction band. How do the moving holes recombine with electrons in the middle of the insulator (there are no free electrons in CB to recombine with) and so they decrease with distance?
  • I can understand in case of transient period before establishing the steady state, that the holes might get trapped in traps and so they decrease with distance. However, when they maintain a dynamic equilibrium of trapping and detraping in steady state, how do the holes decrease in numbers? (Seems like there are infinite traps and so the injected holes keep filling the trap without detraping.)
  • Suppose that the cathode inject electrons to move through conduction band allowing holes to recombine them. But now, is it purely a hole current ? is not there electron current contribution ?
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