the rate constant for a transformation is generally given by: k=k0exp(-Q/RT), ie. ln(k) is inversely proportional to 1/T. but during cooling, the temperature decreases as the transformation occurs whereas ln(k) increases. My question is : how can we consider the rate constat k for transformation occuring during cooling?
Giuma Fellah
I think you have to integrate the equation between the initial and final temperature, also if Q not constant, then you should have the relation between Q and T
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Nabil Kherrouba
Thank you so much. I found the relation in its differential form and I integrate it.
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