To make 2 mM of ferrous chloride (FeCl2), you will need to determine the molecular weight of FeCl2 and calculate the required mass of the compound based on the desired concentration. The molecular weight of FeCl2 is 126.707 g/mol, so to make 2 mM of the compound, you will need to weigh out 0.253514 g of FeCl2.
Once you have the required mass of FeCl2, you can make the solution by dissolving the compound in water. To do this, follow these steps:
Weigh out 0.253514 g of FeCl2 and transfer it to a clean, dry container.
Add a small amount of distilled water to the container and stir to dissolve the FeCl2.
Slowly add more water to the container, stirring constantly, until the desired volume of solution is reached.
Adjust the pH of the solution to 7 using a pH buffer solution or a suitable pH-adjusting agent.
Stir the solution thoroughly to ensure that it is homogeneous and that all of the FeCl2 has dissolved.
Transfer the solution to a clean, labeled container for storage or use.
It is important to note that the exact volume and pH of the final solution may vary depending on the specific conditions and requirements of the application. Therefore, it is always best to consult with a chemist or other expert to determine the appropriate concentration, volume, and pH of the solution.
On purifying ferrous chloride sol. in aq. dil. HCl from ferric iron impurities; cf. my post at: https://www.researchgate.net/post/How_can_i_dissolve_the_FeCl2_salt_in_the_aqueous_solution_while_the_ultimate_pH_be_about_31