you may use this,

%example

a=[1 1 0 0 0 1 1 1 1 1 0 1 0 0 0 1 1 1 1 1 1 1 1 0 0 1 1 1 0];

b=[0 a(1:end-1)]-a;

startt=find(b==-1);

endd=find(b==1)-1;

if M is a  m dimensional matrix by M=M(:), it will converte to one dimensional matrix

Thank you Mr.Hossein Soleimani, it worked well for me.

 %The answer given by Hossein Soleimani is very good and very short

% You can also use this code:

clc

a=[1 1 0 0 0 1 1 1 1 1 0 1 0 0 0 1 1 1 1 1 1 1 1 0 0 1 1 1 0];

z=[0 a];

start=[];end1=[]

flag=0;

for i=1:(length(z)-1)

if and(z(i+1)~=z(i),(flag==0))

start=[start i];

flag=1;

else if and(z(i+1)~=z(i),(flag==1))

end1=[end1 i-1];

flag=0;

end

end

end

[start' end1']

Thank you Yannis Karnavas ji