Kajjali is made from organically purified mercury and organically purified sulfur in equal proportions or sulfur taken in more parts than Mercury.After prolonged trituration it results in a black superfine powder of Kajjali which has to be lusterless.The bond formed between them is a loosely covalent bond.How can we determine its exact chemical structure as it can be triturated with herbal juices also which lend it a trace elements of organic nature.
Bond Structure in such cases depends on the appklication of Electronegativity
First, please don't call a compound of Hg and S "organometallic" This term is confined to compounds with a direct metal-carbon bond. Naturally a Hg-S compound cannot be "organometallic".
Second, Hg and S can form HgS which has two forms. The red form, known as cinnabar, has a polymeric zigzac chain structure: ... -Hg-S-Hg-S-Hg-S-... with covalent Hg-S bonds with a 236 pm Hg-S bond length. The black form which is metastable, exhibits the sphalerite (zinc blende) structure. The interactions between Hg and S are a bit more ionic in this case. Since the most stable form of HgS is red, the black form is unstable and Hg2S does not exist, I don't believe that you produce mercury sulfide by this procedure.
Furthermore, the black material you are producing is presumably not even a pure compound, but a mixture of things (Michael is probably very right in this point). Therefore, you cannot seriously discuss "the bond structure". You should first try to determine the different species which occur in this mixture.
Personally, I would guess that the material contains largely elemental Hg in finely divided particles. Most of real mercury compounds such as kalomel Hg2Cl2, HgCl2, HgS (there is no Hg2S or HgS2), HgO are NOT black, many of them are colourless, yellow or red. Hg in elemental form is black.
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