Hey Everyone
I would like to prepare ceramic slurry with dispersent and bender but given value of those two elements are expressed in mg/m² how can I convert them to mg/g
Dear Khallok,
imagine that you prepare those contributants for example for 1m².
So for your dispersant d (with given mass coverage d*mg/m²) you will have to take d*mg for that single m² and for the bender b (with given mass coverage b*mg/m²) you have to take b*mg for that single m². Thus the ratio d*mg/(b*mg) will give you the result. The only thing you have to do is to convert the resulting unit 'mg/mg' into 'mg/g' (if you want): d/b*mg/mg= d/b*mg/(10-3 g)= 1000*d/b*mg/g
For the general case of an arbitrary area: you have to calculate in the same way: (d*mg/m²)/(b*mg/m²)= d/b*(mg/mg)=1000*d/b*mg/g.
That's it.
Keep in mind that the volume and hence the density is a function of the temperature.
You need to know/measure the specific surface area of your solid material. This will be expressed as m2/g. With that information, it's straightforward to go from mg/m2 to mg/g. You can also obtain an estimate of the specific surface area via particle sizing techniques such as laser diffraction.
If it helps, a general rule of thumb is that it requires 1-5mg/m2 of surfactant to fully cover particles in common colloidal dispersions. It is often a good starting point in the absence of experimental specific surface area information to use 5% by mass of dispersant.
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